162x^2-8=0

Solution for 162x^2-8=0 equation:

162x^2-8=0

a = 162; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·162·(-8)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*162}=\frac{-72}{324}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*162}=\frac{72}{324}
=2/9
$